The Sphere Does Not Admit a Metric Isometry into a Euclidean Space. – math.stackexchange.com 01:42 Posted by Unknown No Comments Problem. There is no embedding $f:S^2\to \mathbf R^3$ such that for all points $p, q\in S^2$, we have $d_{S^2}(p, q)=d_{\mathbf R^3}(f(p), f(q))$. Here $d_{S^2}$ is the metric on $S^2$ which is ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitAre any electrically propelled missions to the outer solar system being planned? If not why not? – space.stackexchange.comWhy does low efficiency antenna can be used for receiving but not for transmitting? – electronics.stackexchange.comIs shape of ice affect to amount of heat to melt it – physics.stackexchange.comExtraneous and Missing Solution Confusion – math.stackexchange.comPrint an ASCII Pylon – codegolf.stackexchange.com"Schmeckt es Sie?" correct? – german.stackexchange.com
0 Comment to "The Sphere Does Not Admit a Metric Isometry into a Euclidean Space. – math.stackexchange.com"
Post a Comment