About the argument of a complex number – math.stackexchange.com 12:35 Posted by Unknown No Comments I know that the square root of complex number is a multivalued function, and by definition: $\sqrt{z}=w\iff w^2=z$ i.e. the square root of z are the solutions of complex equation $w^2=z$. Problem I ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitHow to transform an image into an "Emmys" type of logo? – graphicdesign.stackexchange.comHow can I make pgfplots table recognize fractions? – tex.stackexchange.comSomewhere On The Tube ...But On Which Lines? – codegolf.stackexchange.comWhy does my iPhone 7 have a laser? – apple.stackexchange.comUnderstanding empty set is closed – math.stackexchange.comTwo definitions of the narrow Mordell-Weil group – mathoverflow.net
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