Return Optional value with ?: operator – stackoverflow.com 10:19 Posted by Unknown No Comments I often need to use optional type for functions: std::optional<int32_t> get(const std::string& field) { auto it = map.find(field); if (it != map.end()) return it->second; ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitApproximating atomic move across file systems? – unix.stackexchange.comLimit finding without L'Hospital's rule – math.stackexchange.comAre constructed mathematical syntaxes discouraged by the mathematical community? – math.stackexchange.comArticles before modified proper nouns – ell.stackexchange.comlimit finding without de l'hospital rule – math.stackexchange.comWhy construction of std::unique_ptr for incomplete type compiles? – stackoverflow.com
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