Problem with the compact version of the definition for "exactly one" – math.stackexchange.com 01:38 Posted by Unknown No Comments According to the definition, if we want to express that there is exactly one $x$ such that $P(x)$, we specify: $\exists x (P(x) \wedge \forall y (P(y) \rightarrow y = x))$ By Existential ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitExcel - user input but retain formula for two circular cells – superuser.comCan the Deflect Missiles ability deflect bullets? – rpg.stackexchange.comIs there a mathematical description of three-part ratios? – math.stackexchange.comWhat makes the Free Cities "free"? – scifi.stackexchange.comAdding labels to a bar chart with multiple data sets – mathematica.stackexchange.comWhat we do about puzzles when we say puzzles? We raise them, cast them, ... or we simply say them? – english.stackexchange.com
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