"Proof" all integrals are zero – math.stackexchange.com 20:10 Posted by Unknown No Comments Given some definite integral over $[a,b]$ make the substitution $ u = x(x-a-b)$. The integral is then transformed to an integral over $[-ab,-ab]$ which is zero. What is wrong with this reasoning? When ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitIs temperature the only charging speed limitation? (updated details) – electronics.stackexchange.comBetter way to add fields to superclass in Java – codereview.stackexchange.comIs temperature the only charging speed limitation? – electronics.stackexchange.comWhat to do about Software Project Managers aggressively overloading the Tech Leads? – workplace.stackexchange.comWhat kind of delay does the A320's fly-by-wire system add? – aviation.stackexchange.comHow to append lines/text to the beginning of a file – unix.stackexchange.com
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