Solving an infinite product of consecutive square roots – math.stackexchange.com 10:03 Posted by Unknown No Comments Given $a$ and $b$ calculate $ab$ $$a=\sqrt{7\sqrt{2\sqrt{7\sqrt{2\sqrt{...}}}}}$$ $$b=\sqrt{2\sqrt{7\sqrt{2\sqrt{7\sqrt{...}}}}}$$ I simplified the terms and further obtained that $ab$ is equal to: ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitHow to align the content between two very simple tables – tex.stackexchange.comHow to exit nano and save to current file automatically? – askubuntu.comIs this series diverging? If not, what's the sum? – math.stackexchange.comWhat are the implications of replacing initiative with "Enemy Phase" and "Player Phase"? – rpg.stackexchange.comIf a CPU has a 16 bit address bus and 8 bit words, how much memory can it address? – superuser.comWhat will happen to Qatar flights from Doha if airspace is ban? – travel.stackexchange.com
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