Solving an infinite product of consecutive square roots – math.stackexchange.com

Solving an infinite product of consecutive square roots – math.stackexchange.com

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Given $a$ and $b$ calculate $ab$ $$a=\sqrt{7\sqrt{2\sqrt{7\sqrt{2\sqrt{...}}}}}$$ $$b=\sqrt{2\sqrt{7\sqrt{2\sqrt{7\sqrt{...}}}}}$$ I simplified the terms and further obtained that $ab$ is equal to: ...

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