Why does GCC move variables to a temporary location before assigning them? – stackoverflow.com 10:14 Posted by Unknown No Comments When looking at some decompiled C code I saw this: movl -0x8(%rbp), %esi movl %esi, -0xc(%rbp) This corresponds to this C code: x = y; This got me thinking: how come gcc moves x to %esi and ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitThrown Player damage modifier in DND 5e – rpg.stackexchange.comAnother Riley Riddle ® – puzzling.stackexchange.comI need to lock (as in "disable") my main keyboard as one letter is not working and it's out of warranty – apple.stackexchange.comI want to play D&D, but for a certain reason – rpg.stackexchange.comWhat's the damage modifier for a thrown character? – rpg.stackexchange.comWord for a place where knowledge is shared – english.stackexchange.com
0 Comment to "Why does GCC move variables to a temporary location before assigning them? – stackoverflow.com"
Post a Comment