Why is foo=bar different from foo= bar? – unix.stackexchange.com 01:11 Posted by Unknown No Comments What is the interpretation of the whitespace in this command foo= bar ? Why are foo=bar and foo= bar interpreted differently Example (Ubuntu bash) developer@1604:~$ foo=bar developer@1604:~$ foo= ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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