Why is `sed expr1 | sed expr2` different to `sed -e expr1 -e expr2` – unix.stackexchange.com 12:10 Posted by Unknown No Comments I was splitting the output from id to provide a more readable line-by-list list of groups of which a user is a member: id roaima | sed 's/,/\n\t/g' uid=1001(roaima) gid=1001(roaima) groups=1001(... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitPhoenix Spark VS Disintegrate – rpg.stackexchange.comWhy did Mark Hamill want everyone to “flip the bird” in tribute to Carrie Fisher? – scifi.stackexchange.comHow does a router obtain its IP Address – superuser.comBeing accused of interview fraud after working 2 years – workplace.stackexchange.comWord request: a period of time in which someone's best work was done – english.stackexchange.commagento 1.9 based on condition change checkout/onepage layout – magento.stackexchange.com
0 Comment to "Why is `sed expr1 | sed expr2` different to `sed -e expr1 -e expr2` – unix.stackexchange.com"
Post a Comment