How would you calculate this limit? – math.stackexchange.com

The limit $\displaystyle \lim_{x\to\infty}{\displaystyle \left(1+\frac{1}{3x}\right)}^{4x}$ apparently has a value of $e^{4/3}$. I can't see why this would be the case. EDIT: There was a typo in my ...

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