Summation involving integral – math.stackexchange.com

QuestionThe value of $\sum_{r=1}^{n}\int_{0}^{1}f\left(r+x-1\right)dx$ is equal to $\left(a\right)\int_{0}^{1}f\left(x\right)dx$ $\left(b\right)$n$\int_{0}^{1}f\left(x\right)dx$ ...

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