Why isn't there a endianness modifier in C++ like there is for signedness? – stackoverflow.com 06:18 Posted by Unknown No Comments (I guess this question could apply to many typed languages, but I choose to use C++ as an example.) So, why there no way to just write: struct foo { little int x; // little-endian big long ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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