bash changes its behavior depending on the value of the "IFS" variable – unix.stackexchange.com 20:34 Posted by Unknown No Comments When I set the IFS variable to a space, bash treats multiple spaces as one space (myprogram is a program that prints the command line arguments it receives): IFS=" " x="hello hi world" ./... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitA movie about a cannibalistic football team – movies.stackexchange.comUser can't navigate to a webpage through UI due to permissions, but are able to navigate to that page by pasting the url. How to protect against this? – security.stackexchange.comDoes breaking the actual glyph trigger the effect of a Glyph of Warding? – rpg.stackexchange.comIn the US why is nationalism equated with racism? – politics.stackexchange.comWhat does the angular compiler "compile"? – stackoverflow.comWhat is the identity arrow in this category? – math.stackexchange.com
0 Comment to "bash changes its behavior depending on the value of the "IFS" variable – unix.stackexchange.com"
Post a Comment