Does V = Ultimate L imply GCH? – mathoverflow.net

Does V = Ultimate L imply GCH? – mathoverflow.net

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In his Midrasha Mathematicae lectures ("In Search of Ultimate $L$", BSL 23 [2017]: 1–109), Woodin notes that $V = \textit{Ultimate }L$ implies $\textrm{CH}$ (Theorem 7.26, p.103). Is it known whether ...

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