How many 3-digit numbers can be formed using the digits 2,3,4,5,6,8 such that the number contains the digits 5 and repetitions are allowed? – math.stackexchange.com

How many 3-digit numbers can be formed using the digits 2,3,4,5,6,8 such that the number contains the digits 5 and repetitions are allowed? – math.stackexchange.com

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The solution I have is by counting the complement which gives an answer of $91$. But I think that it should be solved as follows- Let the 3-digit number be denoted by $3$ boxes. We can put the digit ...

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