How to evaluate the given limit – math.stackexchange.com

How to evaluate the given limit – math.stackexchange.com

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Find the value of $\lim_{x\to 0} \dfrac{x^2\sin {\dfrac{1}{x}}}{\sin x}$. Below I am showing my attempt at the question: $x^2\sin {\dfrac{1}{x}}\to 0$ as $x\to 0$ since $\sin {\dfrac{1}{x}}$ is ...

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