Proving inequality with squares – math.stackexchange.com

Proving inequality with squares – math.stackexchange.com

14:09 No Comments
I need to prove that for all $x,y\geq1$ : $$\frac{x+y+1}{\sqrt{x^2+x}+\sqrt{y^2+y}}\leq2$$ I have tried assuming that $$\frac{x+y+1}{\sqrt{x^2+x}+\sqrt{y^2+y}}>2$$, and get some contradiction, ...

from Hot Questions - Stack Exchange OnStackOverflow
via Blogspot

Share this

Unknown

0 Comment to "Proving inequality with squares – math.stackexchange.com"

Post a Comment

Subscribe to: Post Comments (Atom)