Reason why in Gaussian integers, norm divisibility many not lead to divisibility. – math.stackexchange.com 22:19 Posted by Unknown No Comments It is taken as true (with a very easy proof) for Gaussian integers, that for $α, β \in \mathbb {Z}[i]$, if $\beta \mid \alpha \implies N_{\beta} \mid N_α \in \mathbb {Z}$. It is an aid for easier ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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