Reason why in Gaussian integers, norm divisibility many not lead to divisibility. – math.stackexchange.com 22:19 Posted by Unknown No Comments It is taken as true (with a very easy proof) for Gaussian integers, that for $α, β \in \mathbb {Z}[i]$, if $\beta \mid \alpha \implies N_{\beta} \mid N_α \in \mathbb {Z}$. It is an aid for easier ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitHow to step down from 4.5V to 3.3V? – electronics.stackexchange.comMtg Puncturing Light Ruling – boardgames.stackexchange.comWould it hurt racial balance if every PC gets a bonus feat at level 1? – rpg.stackexchange.comWho was the dead Voyager crew member discovered by the two Voth archaeologists? – scifi.stackexchange.comRealistic 'hacks' that programmer may exploit in a brand new FTL comm system that was not securely written? – worldbuilding.stackexchange.comIs 100 hours per year of teaching a heavy load for a lecturer? – academia.stackexchange.com
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