Tan function is a bijection – math.stackexchange.com 03:37 Posted by Unknown No Comments let $f : (-\frac{\pi}{2},\frac{\pi}{2}) \to \mathbb{R}$ be a function so $f(x)=\tan(x)$. I am trying to prove that $f$ is bijective. Firstly I want to show that $f$ is injection. Consider $x,y\in ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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