Difficult geometry question, does not seem to require difficult concepts. – math.stackexchange.com

$\triangle ABC$ has $AC=BC$, and $\angle ACB=96^o$. $D$ is a point in $\triangle ABC$, such that $\angle DAB=18^o, \angle DBA=30^o$. What is $\angle ACD$? My attempt: $\angle ABC=\angle ...

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