How to remove a part of a column using awk – unix.stackexchange.com

How to remove a part of a column using awk – unix.stackexchange.com

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I have this : 2018:01:02-23:52:48 2018:01:02-23:52:48 2018:01:02-23:52:48 2018:01:03-09:26:20 2018:01:03-09:26:20 I want to keep the date, but not the hour in order to sort the number of messages ...

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