Is hyperbolic rotation really a rotation? – math.stackexchange.com

Is hyperbolic rotation really a rotation? – math.stackexchange.com

00:23 No Comments
We define a $2\times 2$ Givens rotation matrix as: $${\bf G}(\theta) = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) &\cos(\theta) \end{bmatrix}.$$ On the other hand, we ...

from Hot Questions - Stack Exchange OnStackOverflow
via Blogspot

Share this

Unknown

0 Comment to "Is hyperbolic rotation really a rotation? – math.stackexchange.com"

Post a Comment

Subscribe to: Post Comments (Atom)