Limits without L'Hopital – math.stackexchange.com

I have a problem finding $$\lim_{x\to 0} \frac{e^{3x}-e^{-4x}}{\sin5x}.$$ I know that L'hopital's rule can be used to get the answer of $\dfrac{7}{5}$, but I tried to do it without the L'hopital. I ...

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