Sum of cube roots of complex conjugates – math.stackexchange.com 07:38 Posted by Unknown No Comments When solving the following cubic equation: $$x^3 - 15x - 4 = 0$$ I got one of the solutions: $$x = \sqrt[3]{2 {\color{red}+} 11i} + \sqrt[3]{2 {\color{red}-} 11i}$$ When I calculated it with a ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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