Spivak's Calculus: Chapter 1, Problem 18b (Quadratic determinant less than zero) – math.stackexchange.com 13:10 Posted by Unknown No Comments The problem in question is as follows: 18b Suppose that $b^2 -4c \lt 0$. Show that there are no numbers $x$ that satisfy $x^2 + bx + c = 0$; in fact, $x^2 + bx + c \gt 0$ for all $x$. Hint: complete ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitI am Chinese. Which name is my surname and which is my last name, for a flight booking? – travel.stackexchange.comAre (literal) cliff hangers still used as cliffhangers? – movies.stackexchange.comFit a word into an alphabet grid – codegolf.stackexchange.comSum the rows of the concatenated triangle – codegolf.stackexchange.comPolynomial divisions: finding the remainder – math.stackexchange.comWhy does the udp port not open? – unix.stackexchange.com
0 Comment to "Spivak's Calculus: Chapter 1, Problem 18b (Quadratic determinant less than zero) – math.stackexchange.com"
Post a Comment