Why P(A|B) does not equal to P(A | B,C) + P(A | B, Not_C)? – stats.stackexchange.com

Why P(A|B) does not equal to P(A | B,C) + P(A | B, Not_C)? – stats.stackexchange.com

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I suppose that $$P(A|B) = P(A | B,C) * P(C) + P(A|B,\neg C) * P(\neg C)$$ is correct, whereas $$P(A|B) = P(A | B,C) + P(A|B,\neg C) $$ is incorrect. However, I have got an "intuition" about ...

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