Writing a high order function to capture common pattern haskell – stackoverflow.com 11:06 Posted by Unknown No Comments f1 [] = 1 f1 (x:xs) = x * f1 xs f2 [] = 0 f2 (x:xs) = 1 + f2 xs f3 [] = 0 f3 (x:xs) = x + f3 xs f4 [] = [] f4 (x:xs) = x ++ f4 xs These all have a common behavior, how exactly can I identify the ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Unknown
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