Why is the regularization term added to the cost function? – stats.stackexchange.com 04:11 Posted by Unknown No Comments Whenever regularization is used, it is often added onto the cost function such as in the following cost function. $$ J(\theta)=\frac 1 2(y-\theta X^T)(y-\theta X^T)^T+\alpha||\theta||_2^2 $$ This ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitWhat's the word for someone who opposes a generally established opinion? – english.stackexchange.comGrep for possible results – unix.stackexchange.comWhat does "tangent" mean? – english.stackexchange.comRam Solutions Group, genuine or scammer? – money.stackexchange.comI don't understand clearly why the ideal sources that the value doesn't match can't be connected – electronics.stackexchange.comWhy did stock brokers go bankrupt after the crash of '29? – history.stackexchange.com
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