Why is the regularization term *added* to the cost function (instead of mutiplied etc.)? – stats.stackexchange.com

Why is the regularization term *added* to the cost function (instead of mutiplied etc.)? – stats.stackexchange.com

06:46 No Comments
Whenever regularization is used, it is often added onto the cost function such as in the following cost function. $$ J(\theta)=\frac 1 2(y-\theta X^T)(y-\theta X^T)^T+\alpha\|\theta\|_2^2 $$ This ...

from Hot Questions - Stack Exchange OnStackOverflow
via Blogspot

Share this

Unknown

Artikel Terkait

0 Comment to "Why is the regularization term *added* to the cost function (instead of mutiplied etc.)? – stats.stackexchange.com"

Post a Comment

Subscribe to: Post Comments (Atom)