BAC─CAB rule used on del operators – physics.stackexchange.com

BAC─CAB rule used on del operators – physics.stackexchange.com

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In my textbook, it is stated that $\nabla\times(\nabla\times A)=\nabla(\nabla\cdot A)-\nabla^2A $ So, I thought that del can be treated as if it were a vector (although it was an operator). However, ...

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