Why is that in the action principle, the Taylor's series is limited to the first order? – physics.stackexchange.com 03:13 Posted by Unknown No Comments For the Hamilton's principle: $$\delta s =\int_{t_1}^{t_2}L(\mathbf {q+\delta q},\mathbf {\dot q+\delta \dot q},t) dt-\int_{t_1}^{t_2}L(\mathbf {q},\mathbf {\dot q},t) dt=0.\\$$ In the textbooks, ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitWhat do you call a building where you can view a historical attraction? – english.stackexchange.comIn which regions or dialects is the Schmetterling called "Buttervogel"? – german.stackexchange.comtikz and commands – tex.stackexchange.comAddressing a professor - culture clash – academia.stackexchange.comFined for driving in NY with foreign drivers license – travel.stackexchange.comDoes there always exist a sub sequence which converges to an arbitrary number between limit superior and limit inferior of a bounded sequence? – math.stackexchange.com
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