Yet another sum of series – math.stackexchange.com 10:53 Posted by Unknown No Comments I need to show that for some $k\in\mathbb{N}, |a|<1,$ $$\sum_{i=0}^\infty {k+i \choose k}a^i=\frac1{(1-a)^{k+1}}.$$ It's technically a power series in $a$ but no approach in that direction proved ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitAlternative proof for continuity of matrix inversion – math.stackexchange.comIs faith necessary for man to survive / why is existentialism valued if it is unsubstantiated? – philosophy.stackexchange.comWhat is an idiomatic way to tell someone to put their hands on someone's eyes in order to not let them see? – ell.stackexchange.comIs there a non stressed ё? – russian.stackexchange.comgetting ducks in example images – tex.stackexchange.comThird time the charm – codegolf.stackexchange.com
0 Comment to "Yet another sum of series – math.stackexchange.com"
Post a Comment