Yet another sum of series – math.stackexchange.com 10:53 Posted by Unknown No Comments I need to show that for some $k\in\mathbb{N}, |a|<1,$ $$\sum_{i=0}^\infty {k+i \choose k}a^i=\frac1{(1-a)^{k+1}}.$$ It's technically a power series in $a$ but no approach in that direction proved ... from Hot Questions - Stack Exchange OnStackOverflow via Blogspot Share this Google Facebook Twitter More Digg Linkedin Stumbleupon Delicious Tumblr BufferApp Pocket Evernote Unknown Artikel TerkaitIs it rude to drive at the speed limit on dangerous roads when another driver wants to go faster? – interpersonal.stackexchange.comHow to create a for loop in math mode – tex.stackexchange.comAre huge, static objects like environment transmitted from server to client in modern multiplayer games? – gamedev.stackexchange.comWhy is the Doctor overwhelmingly male? – scifi.stackexchange.comWhy do C# try catch blocks behave like other code blocks? – softwareengineering.stackexchange.comHow might the chinese government be blocking some Whatsapp traffic? – security.stackexchange.com
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