Deriving the variance of the Bernoulli distribution – math.stackexchange.com

Deriving the variance of the Bernoulli distribution – math.stackexchange.com

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For a Bernoulli distribution, $\mu_X = p$. I can easily derive this from the general equation for mean of a discrete random variable: $$ \mu_X=\sum_{i=1}^kx_iPr(X=x) $$ $$ \mu_X=1(p)+0(1-p)=p $$ I ...

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